What is the square root of #25# ?
1 Answer
Feb 24, 2017
Explanation:
A square root of a number
#x^2 = n#

Every positive number
#n# has two distinct square roots, designated#sqrt(n)# (its positive, principal square root) and#sqrt(n)# . 
Zero has one (repeated) square root, namely
#0# . 
Every negative number
#n# has two distinct pure imaginary square roots, namely#sqrt(n)i# and#sqrt(n)i# , where#i# is the imaginary unit.
[I really dislike the term "imaginary"  such numbers are just as "real" as real numbers].
In our example we find:
#5^2 = 25#
So