# Question #0222b

Feb 26, 2017

Molarity = $0.00728 M$

#### Explanation:

given mass of $K B r$ = $1.70 g$
Molar mass of $K B r$= $119.002$ g/mol
no. of moles $K B r$ = $\frac{1.70}{119.002}$ = $0.0142$ moles

Volume of solution = $1.95 L$
Molarity = $\frac{0.0142}{1.95}$ = $0.00728 M$