# Question #38d90

Jul 11, 2017

I got $1600 {\text{ft}}^{2}$

#### Explanation:

Consider the diagram:

here we can see two rectangles:

the small one of dimensions $100 \text{ft}$ and $50 \text{ft}$

the big one of dimensions $\left[100 + \left(2 \cdot 5\right)\right] \text{ft}$ and $\left[50 + \left(2 \cdot 5\right)\right] \text{ft}$ formed considering also the walk.

Subtracting the area of the small one from the area of the big one we should get the area of the walk.

$A = \left[100 + \left(2 \cdot 5\right) \times 50 + \left(2 \cdot 5\right)\right] - \left[100 \times 50\right] = 6600 - 5000 = 1600 {\text{ft}}^{2}$