Question

If `f(x) = 2 - x - x^2`, then what is `f(–1)+ f(0)`?

Answer 1

The answer is 4.

Explanation:

If `f(x)=2-x-x^2`, then

`f("-1")+f(0)`
`=[2-("-1")-("-1")^2] + [2-(0)-(0)^2]`
`=[2+1-1] + [2]`
`=4`