Question

`sqrt167` lies between which two successive integers?

Answer 1

12 and 13

Explanation:

Let `n` be the lower of the successive integers.

Thus: `n< sqrt167<(n+1)` `[n in ZZ]`

`sqrt167 ~= 12.9228`

`:. n =`the interger part of `12.9338 = 12`

Hence: `12< sqrt167<13`

To check this result:

Consider `12^2 = 144` and `13^2 = 169`

and `144<167<169`