Question #78bc0 Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer P dilip_k Mar 1, 2017 6sin4x =64×(2sin2x)2 =32×(1−cos2x)2 =32×(1−2cos2x+cos22x) =32×(1−2cos2x+12(1+cos4x)) =34×(3−4cos2x+cos4x)) Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for sin2x=cosx for the interval [0,2π]? How do you find all solutions for 4sinθcosθ=√3 for the interval [0,2π]? How do you simplify cosx(2sinx+cosx)−sin2x? If tanx=0.3, then how do you find tan 2x? If sinx=53, what is the sin 2x equal to? How do you prove cos2A=2cos2A−1? See all questions in Double Angle Identities Impact of this question 1693 views around the world You can reuse this answer Creative Commons License