Question #4ef43

1 Answer
Mar 9, 2017

Answer:

#10.2*molxxN_A#, where #N_A="Avogadro's Number.."#

Explanation:

#10.2*molxxN_A#, where #N_A="Avogadro's Number.."#

And #"Avogadro's Number"# #=# #6.022xx10^23*mol^-1#

And thus in #10.2*mol# zinc, there are.........

#~=# #6.022xx10^22# #"zinc atoms"#,