Question #2258a Calculus Limits Classifying Topics of Discontinuity (removable vs. non-removable) 1 Answer Jim H Aug 14, 2017 f is not continuous at -4 and at 1 Explanation: f is continuous at every x in its domain. The domain is all real x where the denominator is not 0. So, f is not continuous at the solutions to x^2+3x-4 which is at -4 and at 1 Answer link Related questions How do you find discontinuity algebraically? How do you find discontinuity of a piecewise function? How do you find discontinuity points? How do you find the discontinuity of a function? How can you remove a discontinuity? How do i find discontinuity for a function? How do you find a removable discontinuity for a function? How do you find the discontinuity of a rational function? What does discontinuity mean? What does discontinuity mean in math? See all questions in Classifying Topics of Discontinuity (removable vs. non-removable) Impact of this question 1518 views around the world You can reuse this answer Creative Commons License