Question

Question #eacef

Answer 1

`approx 445.3 \ ms^(-1)`

Explanation:

The most probable velocity follows from the Maxwell-Boltzman distribution and is:

`v = \sqrt ((2RT)/(M)) approx 445.3 \ ms^(-1)`

With:

• gas constant `R = 8.314`

• molar mass `M = 109 g`

Rest of question is missing information.