Question #cd8ef

1 Answer
Mar 6, 2017

Answer:

#-1#

Explanation:

#sqrt(2)/(2xx-sqrt(2)/2)#

This is the same as:

#sqrt(2)/(2/2xx-sqrt(2))#

But #2/2=1#

#sqrt(2)/(-sqrt(2)) = -1#

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To get the maths formatting you write:

root 2 over 2 times negative root 2 over 2

as: hash sqrt(2)/(2xx-sqrt(2)/2) hash

where hash #-> "## key