Question

Question #f690e

Answer 1

`y=+-sqrt((x+3)/2)`

Explanation:

Set `" "y=2x^2-3`

Make `x` the dependant variable

Add 3 to both sides

`y+3=2x^2`

Divide both sides be 2

`(y+3)/2=x^2`

Square root both sides

`x=+-sqrt((y+3)/2)`

Where there is an `x` write `y` and where there is a `y` write `x`

`y=+-sqrt((x+3)/2)`

Note that the inverse function of `f(x)` is its reflection about the line `y=x`