How many milligrams in a $1.36 \cdot g$ $1.36*g$ mass?

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Answer 1 · 2017-03-07T05:48:20

$1 \cdot g \equiv 1000 \cdot m g$ $1*g-=1000*mg$ ........

The prefix $milli$ $"milli"$ $\equiv$ $-=$ $\times 10^{- 3}$ $xx10^-3$

And thus $1 \cdot g \equiv 10^{3} \cdot m g$ $1*g-=10^3*mg$ .

So a $1.36 \cdot g$ $1.36*g$ mass $\equiv$ $-=$ $(1.36*cancelg)/(10^-3*cancelg*mg^-1)=1360*mg$

How many milligrams in a 1.36*g1.36⋅g1.36*g mass?