Question

Question #400e8

Answer 1

`(dy)/(dx)=tanx+xsec^2x`

Explanation:

this will require the product rule for differentiation

`y=uv=>(dy)/(dx)=u'v+uv'`

where both `" "u" " & " "v" are both functions of"`x#

`y=xtanx`

`u=x=>u'=1`

`v=tanx=>v'=sec^2x`

`(dy)/(dx)=tanx+xsec^2x`