# Question #b83a8

##### 1 Answer

#### Explanation:

A solution's **mass by mass percent concentration**, *weight by weight* percent concentration, **for every** **of said solution**.

In your case, a **for every** **of solution**.

You can use the mass by mass percent concentration as a *conversion factor* to determine the mass of solution that would contain

#19 color(red)(cancel(color(black)("g HCl"))) * overbrace("100 g solution"/(17color(red)(cancel(color(black)("g HCl")))))^(color(blue)("= 17% m/m HCl")) = color(darkgreen)(ul(color(black)("110 g solution")))#

The answer must be rounded to two **sig figs**, the number of sig figs you have for the solution's mass by mass percent concentration and for the mass of hydrochloric acid.