Question

Question #2f974

Answer 1

`P_1 = 2.249atm`

Explanation:

The combined gas law is to be used
`(P_1V_1)/T_1 = (P_2V_2)/T_1`

Where P = pressure(in atm)
V = volume(in litres)
T = temperature in kelvin

convert the units to the appropriate units

`T_1 = 33^oC + 273K = 306K`

`V_1 = 774mL = (774mL)/(1000mL) = 0.774L`

`V_2 = 1229mL = (1229mL)/(1000mL) = 1.229L`

`T_2 = 51^oC + 273K = 324K`

`P_2 = 1.5atm`

Plug in the variables

`(P_1 xx 0.774L)/(306K) = (1.5atm xx 1.229L)/(324K)`

`(P_1 xx 0.774L)/(306K) = 0.00569`

`0.00253xxP_1 = 0.00569`

`P_1 = 0.00569/0.00253 = 2.249atm`