# In a carbonyl oxygen, why do we say that the electrons are trigonal planar?

And for $R C \left(= O\right) O H$, the carbonyl oxygen is $s {p}^{2}$ hybridized, and $O H$ is $s {p}^{3}$ hybridized. Because each oxygen atom is formally neutral we conceive that there are 8 electrons around each oxygen nucleus. Two of these electrons are inner core. The remaining 6 are valence shell, and determine the geometry about oxygen.