# Solve 7/e^-x -4 =1 ?

Mar 20, 2017

$x = \ln \left(\frac{5}{7}\right) \cong - 0.3365$
[If the equation is interpreted as: $\frac{7}{e} ^ - x - 4 = 1$]

#### Explanation:

Since the syntax in the original question the equation may be ambigious, I will define the equation as:

$\frac{7}{e} ^ - x - 4 = 1$

$\frac{7}{e} ^ - x = 5$

$7 {e}^{x} = 5$

${e}^{x} = \frac{5}{7}$

$x = \ln \left(\frac{5}{7}\right) \cong - 0.3365$