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Question #444c2

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Mar 21, 2017

I thnk you mean $\frac{M}{V}$ $M/V$ so if you want to make $\frac{1}{100 mL}$ $1/(100"mL")$ or $\frac{10 g}{1000 mL}$ $(10g)/(1000"mL")$

Molar mass of hypochlorite acid = 52.46 g/mol

Moles in 10grams of hypochlorite = $\frac{10}{52.46g/mol}$ $10/"52.46g/mol"$

0.19062142584mol/L or 0.19062142584M of hypochlorite acid acid would be required to make 1% hypochlorite acid

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