# What is the mass of a single ""^20Ne atom?

Mar 21, 2017

We divide the $\text{molar mass}$ by $\text{Avogadro's number.........}$

#### Explanation:

And thus $\text{atomic mass}$ $=$ $\text{Molar mass"/"Avogadro's number}$

$= \frac{20 \cdot g \cdot m o {l}^{-} 1}{N} _ A = \frac{20 \cdot g \cdot \cancel{m o {l}^{-} 1}}{6.022 \times {10}^{23} \cdot \cancel{m o {l}^{-} 1}}$

$= 3.32 \times {10}^{-} 23 \cdot g$.................

Note the dimensional consistency of the quotient; i.e. we wanted an answer with units of mass, and we got one......