What is the percentage composition of each element in #"Freon"#, #CF_2Cl_2#?

1 Answer
Mar 21, 2017

Answer:

Let's work out #%C# #"by mass"#.

Explanation:

#%C="Mass of carbon"/"Molar mass of freon"xx100%=#

#(12.011*g*mol^-1)/(120.91*g*mol^-1)xx100%~=10%#

#%Cl=(2xx"mass of chlorine")/"Molar mass of freon"xx100%=??#

#%F=(2xx"mass of fluorine")/"Molar mass of freon"xx100%=??#

Should the elemental percentages sum to #100%#?