# Question 0dbab

Mar 23, 2017

The percent composition of carbon in a glucose molecule is 40.002%#.

#### Explanation:

Determine the mass of one molecule of glucose. Then divide the mass of carbon by the total mass, then multiply by 100.

Mass of $\text{C"_6"H"_12"O"_6} :$$\text{180.156 u}$
https://www.ncbi.nlm.nih.gov/pccompound?term=glucose

Mass of $\text{C atom} :$$\text{12.011 u}$ (periodic table)

Mass of $\text{C}$ in glucose molecule: $\text{6"xx"12.011 u=72.066 u}$

Percent Composition of Carbon

$\text{% composition C"=(72.066"u")/(180.156"u")xx100"="40.002%}$