# Question #24c97

##### 1 Answer

#### Answer:

#### Explanation:

We use **volume by volume percent concentration** to show how many milliliters of solute are present in

In your case, the solution is **every**

So regardless of the volume of the solution, you can say for a fact that you will have a ratio of

Now, you can use the solution's volume by volume percent concentration as a *conversion factor* to calculate the number of grams of isopropyl alcohol present in

#473 color(red)(cancel(color(black)("mL solution"))) * overbrace("70. mL isopropyl alcohol"/(100color(red)(cancel(color(black)("mL solution")))))^(color(blue)("= 70.% v/v")) = color(darkgreen)(ul(color(black)("330 mL isopropyl alcohol")))#

The answer is rounded to two **sig figs**, the number of sig figs you have for the percent concentration of the solution.