Question #26011

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Answer 1 · 2017-04-27T19:01:06

#P(X<127)=0.9641.#

If #X="RV the IQ of an adult "#

we have

#X~N(100,15^2)#

and require to find

#P(X<127)#

we need to change the #" "X" "# variable we to the standard #Z" "# variable for a Normal distribution using the standardising formula

#Z=(X-mu)/sigma#

#P(Z<(127-100)/15)=P(Z<1.8)#

we now use the standard Normal tables to find this probability

=0.9641

Thus

#P(X<127)=0.9641.#