# Question #65e73

Mar 28, 2017

68.4 litres

#### Explanation:

Assuming all oxygen atoms here are O-16 and that 1 mol of any gas at room temperature and pressure is 24${\mathrm{dm}}^{3}$,

${M}_{r} = \frac{\text{mass of gas}}{{A}_{r}}$, where ${M}_{r}$ is molar mass and ${A}_{r}$ is atomic mass

${M}_{r} = \frac{45.6}{16 \cdot 2} = 2.85 m o l$ (bearing in mind oxygen gas in in the ${O}_{2}$ state)

Therefore, the volume of oxygen is:

${V}_{{O}_{2}} = 2.85 m o l \cdot 24 {\mathrm{dm}}^{3} = 68.4 {\mathrm{dm}}^{3} = 68.4 l$