Question

Question #65e73

Answer 1

68.4 litres

Explanation:

Assuming all oxygen atoms here are O-16 and that 1 mol of any gas at room temperature and pressure is 24`dm^3`,

`M_r=("mass of gas")/(A_r)`, where `M_r` is molar mass and `A_r` is atomic mass

`M_r=45.6/(16*2)=2.85 mol` (bearing in mind oxygen gas in in the `O_2` state)

Therefore, the volume of oxygen is:

`V_(O_2)=2.85 mol*24dm^3=68.4dm^3=68.4 l`