Question #cb7bf

2 Answers
Mar 30, 2017

a -> [L/(T*T)]

b -> [L/T]

c -> [T]

Explanation:

I am considering the equation as :

v = at + b * t/(t+c)

Let me know if this is not what you meant.

In any equation, each term separated by + or - must have same dimension or else cannot be added.

So here v , a*t , and b * t/(t+c) must have same dimension. Since we know the dimension of velocity as [L/T], the other 2 terms should also have the same dimension.

So a*t has dimension [L/T]

[aT] = [L/T]

[a] = [L/(T*T)]

Similarly, let us consider the denominator part of 2nd term. (t + c). Here t and c must have the same dimensions since they are being added, so

[c] = [T]

The rest

[b T/(c+T)] = [L/T]

[bT/T] = [L/T], since c and T are being added

[b] = [L/T]

Hope you have a good day.

Mar 30, 2017

The dimension of a and b is =[L][T]^-1
The dimension of c is [T]

Explanation:

The dimension of c is [T]

The dimension of v is [L][T]^-1

The dimension of at is [L]

The dimension of a is [L][T]^-1

The dimension of b is [L][T]^-1

I considered the equation as

v=((at+bt))/((t+c))

LHS is =[L][T]^-1

RHS is =([L][T]^-1)/[T]*[T]

Therefore,

a is [L][T]^-1