Question #6c51e Calculus Introduction to Integration Definite and indefinite integrals 1 Answer salamat Mar 30, 2017 # x^6/6 - x^5 / 5 -x^4 /2 + c# Explanation: considering your question is #int x^3(x^2 - x -2)# #int x^3(x^2 - x -2) = int x^5 - x^4 -2 x^3# # = x^(5+1)/(5+1) - x^(4+1) /(4 +1) -2 x^(3+1) /(3+1) + c# # = x^6/6 - x^5 / 5 -2 x^4 /4 + c# # = x^6/6 - x^5 / 5 -x^4 /2 + c# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 1035 views around the world You can reuse this answer Creative Commons License