Question #f2b43

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Answer 1 · 2017-03-31T03:20:02

perimeter $= 11.9957 m$
area $=5.8165 m^2$

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I have to assume that the triangle shown in the figure is a right triangle.

To find the perimeter of this shape, we need to add up all the outside edges (the solid green lines and arcs).

$Y=sqrt(4.5^2-3^2)=3.3541m$

perimeter $= 3.3541+4.5+(3-1-1+2*pi*r)$
where r is the radius of the semi-circles ( $r=1/2*$ diameter).

$=>$ perimeter $= 3.3541+4.5+(3-1-1+2*pi*1/2)$
$=11.9957m$

Area of the shape = area of triangle + area of the two semi-circles
$=>$ Area $= (1/2*Y*3) + (pi*r^2)$
$=(1/2*3.3541*3)+(pi*(1/2)^2)$
$=5.8165m^2$