How do you graph #5x-2y=10#?

2 Answers
Mar 31, 2017

Answer:

See the explanation.

Explanation:

Graph:

#5x-2y=10#

This equation is in standard form for a linear equation. You only need two points to graph a straight line. The standard form makes it easy to find the x- and y-intercepts, which can be graphed.

#5x-2y=10#

X-intercept: value of #x# when #y=0#.

Substitute #0# fro #y# and solve for #x#.

#5x-2(0)=10#

#5x=10#

Divide both sides by #5#.

#x=10/5#

#x=2#

The x-intercept is #(2,0)#.

Y-intercept: value of #y# when #x=0#

Substitute #0# for #x# and solve for #y#.

#5(0)-2y=10#

#-2y=10#

Divide both sides by #-2#.

#y=10/-2#

#y=-5#

The y-intercept is #(0,-5)#

Plot the x- and y-intercepts and draw a straight line through the points.

graph{5x-2y=10 [-16.23, 15.8, -10.26, 5.76]}

Mar 31, 2017

Answer:

Find the #x and y#- intercepts and draw a line through them.

Explanation:

If you are given the equation of a straight line in standard form
#(ax+by =c)#, then you can find the #x and y#-intercepts.

To find the #x#-intercept, make #color(red)(y=0)#

#5x-2color(red)(y) = 10" "rarr5x-2color(red)((0)) = 10" "# Solve for #x#
#5x = 10#

#x = 2" "larr# this is the #x#-intercept

To find the #y#-intercept, make #color(blue)(x=0)#

#5color(blue)(x)-2y = 10" "rarr5color(blue)((0))-2y = 10" "# Solve for #y#
#-2y = 10#

#y=-5" "larr# this is the #y#-intercept

Now you can plot the two intercepts on a grid and draw a line passing through both of them. graph{5x-2y = 10 [-6.06, 13.94, -8.06, 1.94]}