Question #5acf3

1 Answer
Eddie
Apr 1, 2017

You can't, because it diverges.

Explanation:

We can check convergence using the integral test :

lim_(a to oo) int_1^a (x)/(4x^2+1) \ dx = lim_(a to color(red)( oo)) [1/8 ln (4x^2+1)]_1^a

This diverges so sum_1^(oo) (n)/(4n^2+1) also diverges.

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