Question

Question #5acf3

Answer 1

You can't, because it diverges.

Explanation:

We can check convergence using the integral test :

`lim_(a to oo) int_1^a (x)/(4x^2+1) \ dx = lim_(a to color(red)( oo)) [1/8 ln (4x^2+1)]_1^a`

This diverges so `sum_1^(oo) (n)/(4n^2+1)` also diverges.