# To how many atmospheres does a pressure of 36*lb*"inch"^2 correspond?

$36 \cdot l b \cdot {\text{inch}}^{-} 2 \cong 2 \cdot a t m$
$1 \cdot a t m \equiv 14.7 \cdot \text{psi}$,
And thus $\left(36.0 \cdot \text{psi")/(14.7*"psi} \cdot a t {m}^{-} 1\right) \cong 2.5 \cdot a t m \ldots \ldots \ldots \ldots$