# What is the "normality" of a 4.0*g mass of sodium hydroxide dissolved in a 1.0*L volume of water?

Apr 8, 2017

$\text{Normality} = 1.0 \cdot N$

#### Explanation:

$\text{Normality}$ is defined similarly to $\text{molarity}$.

$\text{Normality"=("Moles of "H_3O^+"or "HO^-)/"Volume of solution}$

Here, $\text{normality} = \frac{\frac{4.0 \cdot g}{40.0 \cdot g \cdot m o {l}^{-} 1}}{0.100 \cdot L} = 1.0 \cdot N$.

This will react quantitatively with one equiv of acid. One the other hand, a solution of diprotic ${H}_{2} S {O}_{4} \left(a q\right)$ that is $0.50 \cdot m o l \cdot {L}^{-} 1$ with respect to ${H}_{2} S {O}_{4}$, but necessarily $1.0 \cdot m o l \cdot {L}^{-} 1$ with respect to ${H}_{3} {O}^{+}$ (why?), would also be regarded as $1 \cdot N$.