Question #bf4d3

1 Answer
Apr 9, 2017

Answer:

#41%#

Explanation:

First, we need to calculate theoretical yield from the balanced equation.

#4NH_3 + 6NO -> 5N_2 + 6H_2O# this shows that we should get 5 moles of #N_2# for every 4 moles of #NH_3# reacted.
10.0g of #NH_3# is #(10.0/17) = 0.588# moles. The resulting #N_2# should then be #5/4 * 0.588 = 0.735# moles. From this value we can either calculate grams, for a mass/mass % yield, or convert our given grams into moles for a mole/mole (volume/volume) % yield.

Mass basis: #0.735"mol" N_2 * (28g N_2)/(mol N_2) = 20.58# g #N_2# Theoretical #(8.50/20.58 * 100) = 41.3%# by mass

Mole basis: #(8.50g N_2)/((28g N_2)/(mol N_2)) = 0.304# moles #N_2# #(0.304/0.735 * 100) = 41.4%# by volume