How many atoms are present in a #13.9*g# mass of #"carbon disulfide"#?

1 Answer
Apr 14, 2017

Answer:

First we calculate the quotient #"Mass of stuff"/"Molar mass of stuff"#...........

Explanation:

And this quotient gives......#(13.9*g)/(76.14*g*mol^-1)=0.188*mol# with respect to #CS_2#.

Since each mole/molecule of #CS_2# contains 1 mole of carbon, and 2 moles of sulfur, there are #3xx0.188*molxx6.022xx10^23*mol^-1=3.39xx10^23# individual atoms.......