Question

How many atoms are present in a `13.9*g` mass of `"carbon disulfide"`?

Answer 1

First we calculate the quotient `"Mass of stuff"/"Molar mass of stuff"`...........

Explanation:

And this quotient gives......`(13.9*g)/(76.14*g*mol^-1)=0.188*mol` with respect to `CS_2`.

Since each mole/molecule of `CS_2` contains 1 mole of carbon, and 2 moles of sulfur, there are `3xx0.188*molxx6.022xx10^23*mol^-1=3.39xx10^23` individual atoms.......