Question #866be
1 Answer
May 28, 2017
Explanation:
#"Given"#
#z_1=r_1(costheta_1+isintheta_1)#
#z_2=r_2(costheta_2+isintheta_2)#
#rArr(z1)/(z_2)=(r_1)/(r_2)(cos(theta_1-theta_2)+isin(theta_1-theta_2))#
#color(white)(rArrzi/z2)=2/4(cos(90)^@+isin(90)^@)#
#color(white)(xxxxxx)=1/2(0+i)=1/2i#
