# Question #e1fc3

Apr 14, 2017

It would be ${120}^{0}$

#### Explanation:

Given the forces are equal, it would be reasonable to assume they have the same angle between them as in the diagram below:

If we then consider components of forces in the x direction:

${F}_{2} \cos {30}^{0} - {F}_{1} \cos {90}^{0} - {F}_{3} \cos {30}^{0}$
$\implies {F}_{2} \cos {30}^{0} - {F}_{3} \cos {30}^{0}$

Since ${F}_{1} = {F}_{2} = {F}_{3}$ then the above equates to nil

Similarly in the y direction:

${F}_{1} - {F}_{2} \sin {30}^{0} - {F}_{3} \sin {30}^{0}$
$\implies {F}_{1} - 0.5 \cdot {F}_{2} - 0.5 \cdot {F}_{3} = 0$

Hence no resultant force