Question

Question #26091

Answer 1

The new temperature would be 222 °C.

Explanation:

This is an example of a Combined Gas Laws problem.

`color(blue)(|bar(ul((p_1V_1)/T_1=(p_2V_2)/T_2)|)`

We can rearrange this formula to get

`T_2 = T_1 × p_2/p_1 × V_2/V_1`

Your data are:

`p_1 = p_1; color(white)(ll)V_1 = V_1; color(white)(ml)T_1 = "(57 + 273.15) °C" = "330.15 K"`

`P_2 = 3p_1; V_2 = 0.5 V_1`; `T_2 = ?`

`∴ T_2 = 330.15 K × (3color(red)(cancel(color(black)(p_1))))/color(red)(cancel(color(black)(p_1))) × (0.5color(red)(cancel(color(black)(V_1))))/color(red)(cancel(color(black)(V_1))) = "495.22 K" = "222 °C"`

The new temperature would be 222 °C.