Question #26091

1 Answer
Apr 17, 2017

Answer:

The new temperature would be 222 °C.

Explanation:

This is an example of a Combined Gas Laws problem.

#color(blue)(|bar(ul((p_1V_1)/T_1=(p_2V_2)/T_2)|)#

We can rearrange this formula to get

#T_2 = T_1 × p_2/p_1 × V_2/V_1#

Your data are:

#p_1 = p_1; color(white)(ll)V_1 = V_1; color(white)(ml)T_1 = "(57 + 273.15) °C" = "330.15 K"#

#P_2 = 3p_1; V_2 = 0.5 V_1#; #T_2 = ?#

#∴ T_2 = 330.15 K × (3color(red)(cancel(color(black)(p_1))))/color(red)(cancel(color(black)(p_1))) × (0.5color(red)(cancel(color(black)(V_1))))/color(red)(cancel(color(black)(V_1))) = "495.22 K" = "222 °C"#

The new temperature would be 222 °C.