# Question #ee5b2

Apr 20, 2017

$3.16 \cdot {10}^{-} 10$ = [H+]

#### Explanation:

pH = -log [H+]
pOH = -log [OH-]
pH + pOH = 14
[H+] * [OH-] = 1 * 10^-14

using the above equations, you can see there is more than one way to solve this problem. here's how I would do it.

pOH = 4.5
14 - pOH = pH
14 - 4.5 = 9.5
pH = 9.5

pH = -log [H+]
9.5 = -log [H+]
-9.5 = log [H+]
${10}^{-} 9.5$ = [H+]
$3.16 \cdot {10}^{-} 10$ = [H+]