Question #b27d1

1 Answer
Apr 22, 2017

Answer:

#6.022140857 × 10^23#

Explanation:

First, we need to find what percentage of the Calcium Carbonate is Carbon.

The relative atomic mass of Calcium Carbonate is = (#CaCO_3#) = #40 + 12 + (16xx3) = 100#

The relative atomic mass of Carbon is 12, so the percentage of Carbon in Calcium Carbonate is:
#12 / 100 xx 100% = 12%#

So in 100g of Calcium Carbonate, there is 12g of Carbon.
We then find how many moles of Carbon there is:
#"moles" = "mass" / "relative atomic mass"#
So there is #12/12 = 1# mole

In a mole of any substance, there are #6.022140857 × 10^23# atoms - this is known as the Avogadro constant.

Hope this helps:) Let me know if I can do anything else.