How do you simplify #5sqrt3 + 2sqrt27 + 1/sqrt3#?

1 Answer
Jun 6, 2017

#5sqrt3+2sqrt27+1/sqrt3=color(blue)((34sqrt3)/3#

Explanation:

Simplify:

#5sqrt3+2sqrt27+1/sqrt3#

In order to add terms with square roots, the square roots must be the same.

Simplify #2sqrt27# by using prime factorization.

#5sqrt3+2sqrt(3xx3xx3)+1/sqrt3#

#5sqrt3+2sqrt(3^2xx3)+1/sqrt3#

Apply rule: #sqrt(a^2)=a#

#5sqrt3+2xx3sqrt3+1/sqrt3#

Simplify.

#5sqrt3+6sqrt3+1/sqrt3#

Rationalize the denominator in #1/sqrt3# by multiplying by #sqrt3/sqrt3#.

#5sqrt3+6sqrt3+1/sqrt3xxsqrt3/sqrt3#

Apply rule: #sqrtasqrta=a#

#5sqrt3+6sqrt3+sqrt3/3#

In order to add fractions, they must have the same denominator. Multiply the first two terms by #3/3#.

#(3xx5sqrt3)/3 + (3xx6sqrt3)/3 + sqrt3/3#

Simplify.

#(15sqrt3)/3 + (18sqrt3)/3 + sqrt3/3#

Combine all terms.

#(34sqrt3)/3#