# Question #0ea67

Apr 24, 2017

#### Answer:

$8.18 \cdot {10}^{23} a t m s$ of nickel with significant figures.

#### Explanation:

Use dimensional analysis and Avogadro's number:
$79.7 \cdot \left(\frac{1 m o l}{58.69 g}\right) \cdot \left(\frac{6.022 \cdot {10}^{23} a t m s}{1 m o l}\right)$

Then plug it into a calculator to get the answer:
$8.18 \cdot {10}^{23} a t m s$ of nickel with significant figures.

***In case you were wondering, 58.69 g is the mass of one mole of Nickel (you can get this from the periodic table).