Question #0ea67

1 Answer
Apr 24, 2017

Answer:

#8.18 * 10^23 atms# of nickel with significant figures.

Explanation:

Use dimensional analysis and Avogadro's number:
#79.7 * ((1mol)/(58.69g)) *((6.022*10^23 atms)/(1mol))#

Then plug it into a calculator to get the answer:
#8.18 * 10^23 atms# of nickel with significant figures.

***In case you were wondering, 58.69 g is the mass of one mole of Nickel (you can get this from the periodic table).