# Question bd24c

Apr 24, 2017

See below.

#### Explanation:

This is a dimensional analysis problem with the following setup:
$\left(7.370 \cdot {10}^{25}\right) \cdot \left(\frac{1 m o l}{6.022 \cdot {10}^{23}}\right)$

$122.3$ moles Cl2

Apr 24, 2017

$122.4 {\text{ mols Cl}}_{2}$

#### Explanation:

Since Avogadro's number (6.02214179×10^23) is the number of molecules in one mole, all you have to do is divide the given molecules by Avogadro's number.

$\left(7.370 \cdot {10}^{25} {\text{molecules")/(6.02214179×10^23"molecules"*"mole}}^{- 1}\right)$

 #

$\left(7.370 \cdot {10}^{25} \textcolor{red}{{\cancel{\textcolor{b l a c k}{\text{molecules")color(red)" mols")/(6.02214179×10^23color(red)(cancelcolor(black)"molecules")*color(red)(cancelcolor(black)("mole}}}}^{- 1}}\right)$

$122.381708319 \text{ mols}$

Due to the 4 significant figures, the answer would be:

$122.4 {\text{ mols Cl}}_{2}$