# Question #b28f3

Apr 26, 2017

$g r a m s H C l = 339 g r a m s$

#### Explanation:

First, find how many moles of ${H}_{2}$ gas will take up 104 liters.

$\frac{1 m o l {H}_{2} \left(g\right)}{22.4 L} = \frac{\text{x} m o l {H}_{2} \left(g\right)}{104 L}$

$x = 4.642857143 m o l s$

Now use the reaction coefficients to find the moles of hydrochloric acid needed to form the above moles of hydrogen gas.

$m o l s H C l = 4.642857143 m o l s {H}_{2} \cdot \frac{2 m o l s H C l}{1 m o l {H}_{2}}$

$m o l s H C l = 9.285714286$

To find grams of HCl just multiply the moles of HCl by its molar mass.

$g r a m s H C l = 9.285714286 m o l s H C l \cdot 36.46094 \frac{g}{m o l}$.

$g r a m s H C l = 338.565871439 g r a m s$

Since you only have 3 sig figs, the answer would be:

$g r a m s H C l = 339 g r a m s$