# Question #8c5a2

Apr 27, 2017

$3 \cdot {10}^{- 2}$ mols $A {l}_{2} {O}_{3}$

#### Explanation:

By looking at the reaction coefficients in the balanced chemical equation, we see that 2 moles of $A l$ will form one mole of $A {l}_{2} {O}_{3}$.

$m o l s A {l}_{2} {O}_{3} = \frac{m o l s A l}{2}$

$m o l s A {l}_{2} {O}_{3} = 0.03$

Since you have one sig fig, the answer would be:

$m o l s A {l}_{2} {O}_{3} = 3 \cdot {10}^{- 2}$