Question #8c5a2

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Question #8c5a2

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Answer 1 · 2017-04-27T00:31:31

$3 \cdot 10^{- 2}$ $3 * 10^(-2)$ mols $A l_{2} O_{3}$ $Al_2O_3$

Explanation:

By looking at the reaction coefficients in the balanced chemical equation, we see that 2 moles of $A l$ $Al$ will form one mole of $A l_{2} O_{3}$ $Al_2O_3$ .

$m o l s A l_{2} O_{3} = \frac{m o l s A l}{2}$ $mols Al_2O_3 = (mols Al)/2$

$m o l s A l_{2} O_{3} = 0.03$ $mols Al_2O_3 = 0.03$

Since you have one sig fig, the answer would be:

$m o l s A l_{2} O_{3} = 3 \cdot 10^{- 2}$ $mols Al_2O_3 = 3 * 10^(-2)$

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Question #8c5a2

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