How do we represent #"1,2-dimethyl-3-(N-ethylamino)octane"#?

1 Answer
anor277
Apr 28, 2017

Well, write out the octane skeleton first..........

Explanation:

#H_3stackrel1Cstackrel2CH_2stackrel3CH_2stackrel4CH_2stackrel5CH_2stackrel6CH_2stackrel7CH_2stackrel8CH_3#

And so we've got #"n-octane"#.

And then substitute in the functional groups: at #stackrel2C# two methyl groups, and at #stackrel3C#, an #NH(CH_2CH_3)#:

#H_3stackrel1Cstackrel2C(CH_3)_2stackrel3C(NHCH_2CH_3)Hstackrel4CH_2stackrel5CH_2stackrel6CH_2stackrel7CH_2stackrel8CH_3#

Could this molecule generate optical isomerism?

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