# Question #22bcc

Apr 29, 2017

$Z n S {O}_{4} \to Z {n}^{2 +} + S {O}_{4}^{2 -}$
$C u {\left(N {O}_{3}\right)}_{2} \to C {u}^{2 +} + 2 N {O}_{3}^{-}$
Neither $Z n S {O}_{4}$ , $C u {\left(N {O}_{3}\right)}_{2}$ , $Z n {\left(N {O}_{3}\right)}_{2}$ nor $C u S {O}_{4}$ are insoluble in water and therefore all ions will remain in solution.