Question #2927a Algebra 1 Answer EET-AP Apr 29, 2017 #x=2 ; x=3# Explanation: The exponent is #2# so we will get two answers for #x# and that means two sets of brackets: #x^2-5x+6=0# #(x ....)(x ....)=0# To obtain a #-5# in the middle term the factors of #+6# will need to be #2 and 3#, with both being negative: #(x-2)(x-3)=0# #(x-2)=0# #x=2# #(x-3)=0# #x=3# Substitute the values into the #given# equation to check: #x^2-5x+6=0# #2^2-5(2)+6=0# #4-10+6=0# Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 787 views around the world You can reuse this answer Creative Commons License