Question #bce5b

1 Answer
May 3, 2017

Answer:

The specific heat capacity of the material is #"0.6469 J·°C"^"-1""g"^"-1"#.

Explanation:

The formula for the amount heat #q# absorbed by a substance is

#color(blue)(bar(ul(|color(white)(a/a)q = mCΔTcolor(white)(a/a)|)))" "#

where

#m# is the mass of the substance
#C# is the specific heat capacity of the material
#ΔT# is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

#C = q/(mΔT)#

In this problem,

#q = "-86 285 J"#
#m = "863.3 g"#
#ΔT = "(25.00 - 179.5) °C" = "-154.5 °C"#

#C = "-86 285 J"/"863.3 g × (-154.5 °C)" = "0.6469 J·°C"^"-1""g"^"-1"#

Calcium?