Molarity of NaOH
The equation for the reaction with
It took 20.0 mL of NaOH to neutralize 20.0 mL of HA, so the two solutions must have had the same concentration, i.e. 0.10 mol/L.
As long as we have some
At the mid-point of the titration (i.e. at 10.0 mL
Taking the negative logarithm of both sides, we get
At half-neutralization (10.0 mL),