Question

Question #3d499

Answer 1

`T_2 = 381^@"K"`

Explanation:

Convert the temperature to Kelvin scale:

`T_1 = 32^@"C"+273^@"C" = 305^@"K"`

Start with the combined Gas Law:

`(P_1V_1)/T_1 = (P_2V_2)/T_2`

Solve for `T_2`

`T_2 = (T_1P_2V_2)/(P_1V_1)`

`T_2 = ((305^@"K")(1.45xx10^3"mm Hg")(108"ml"))/((745"mm Hg")(168"ml"))`

`T_2 = 381^@"K"`