Question #36999

1 Answer
Jul 18, 2017

g'(x)=e^x(x^2+2x)

g''(x)=e^x(x^2+4x+2)

Explanation:

We will use the product rule.

g'(x)=(x^2)'e^x+x^2(e^x)'=2xe^x+x^2e^x=e^x(x^2+2x)

g''(x)=(e^x)'(x^2+2x)+e^x(x^2+2x)'=

e^x(x^2+2x)+e^x(2x+2)=e^x(x^2+4x+2)